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MIT 6.002 Circuits and Electronics, Spring 2007 13 Online
OpenStudy (anonymous):

finally completed the midterm :-)

OpenStudy (anonymous):

how???

OpenStudy (anonymous):

Help for Midterm3 formula pls, or for what change zender diode

OpenStudy (anonymous):

well done - if you wouldn't mind, could you post your formula for question 1, potentially 3-8 please?

OpenStudy (anonymous):

give me 10 min will give answer to q3 and a1 @ppich give me the values of ur q3

OpenStudy (anonymous):

no no plzz give the formulae or hints on how to do questions

OpenStudy (anonymous):

just how change zender diode

OpenStudy (anonymous):

@ppich tell me all the parts of ur midterm q3 then only i will be able to help u out \

OpenStudy (benzo):

lucky12345 congrats....could you give me the formula for q1..A and B also R, V. I....im stuck mannn

OpenStudy (anonymous):

Assuming that I=9A, what is the value of the voltage vo (in Volts)?

OpenStudy (anonymous):

Now assuming that I=−3A, what is the value of the voltage vo (in Volts)? Finally, for the last two parts assume that I=4A.

OpenStudy (qaisersatti):

what are the formula for Q1

OpenStudy (anonymous):

@lucky12345 could you help me with q1 q3 q6 please

OpenStudy (anonymous):

midterm q1 current through R1 =current through R2 =(V1-R3(I1-I2))/(R1+R2+R3) current through R3 =(V1-(R1R2)(I1-I2))/(R1+R2+R3) 1. Va=(current through R2)*R2+Vb 2. Vb=(current through R3 )*R3 3. power in R1= current through R1*current through R1*R1 4. power in R2=current through R2*current through R2*R2 5. power in R3=current through R3*current through R2*R3 6. power in V1=V1*current through R1 7. power in i1=Vb*current through R3 8. power in i2=-Vb*current through R3

OpenStudy (anonymous):

@ppich answers are 2 -1 1.3333333 2.666666

OpenStudy (anonymous):

trust me just go for these answers

OpenStudy (anonymous):

@lucky12345 , thanks a heap brother for question 1

OpenStudy (anonymous):

The circuit elements have the following values: Vin=42V, R1=4Ω, R2=4Ω, R3=7Ω, A=1.5 and B=0.125. for midterm6 if you know

OpenStudy (anonymous):

if u find it helpful click best response

OpenStudy (anonymous):

@lucky12345 , Thanks bro ! kindly , post the formulas used in question 6 ?

OpenStudy (anonymous):

congrats pls give formulae for q3 of midterm!!!!!

OpenStudy (anonymous):

thak you may ask for midterm 5 Here, VS=90V, R=6kΩ, and the transistor parameter f=0.5mAV3. The amplifier is biased with VIN=2V. that Vout=Vs-(f*(VIN^3))*R is this right

OpenStudy (anonymous):

ya its right

OpenStudy (anonymous):

congrats pls give formulae for q3 of midterm!!!!!

OpenStudy (anonymous):

@lucky12345 , Thanks bro ! kindly , post the formulas used in question 6 ?

OpenStudy (qaisersatti):

what abt Q2 and 3...:)

OpenStudy (anonymous):

@lucky12345 , Thanks bro , but what about the last part of question 6 ??

OpenStudy (anonymous):

@Qaisersatti q2 is the most simple one just refer HW3P1 u will find the answer there with solution

OpenStudy (qaisersatti):

thanks brother....actually i am travelling thats why i asked i will go to H3P1

OpenStudy (anonymous):

Rth for thevelin have a formula

OpenStudy (anonymous):

@ppich , can u tell me the formula for question 6 , the last part ???

OpenStudy (anonymous):

but what about the other part @ppich for Q5

OpenStudy (benzo):

lucky q1 (6-(1000*400)(2-2))/(1000+400+600) it said invalid syntax.......i was following what you post (V1-(R1R2)(I1-I2))/(R1+R2+R3)

OpenStudy (anonymous):

@lucky12345 buddy for the first question i get the last two bits as incorrect could you help me out please

OpenStudy (anonymous):

@ppich hey buddy seems that we both have the same values so could you please help me out!! i would be grateful to youy

OpenStudy (anonymous):

thanks a lot @ppich

OpenStudy (anonymous):

@muthukrishna241994 : power through i1= vb*I1 power by i2 = -vb*i2

OpenStudy (benzo):

ali_amjad please help....what v1 the formula please

OpenStudy (benzo):

midterm q2 formula please appreciate your help anyone?

OpenStudy (anonymous):

@benzo do you got answers for Q1 and Q2 completely??

OpenStudy (benzo):

what question ali

OpenStudy (anonymous):

RTH please, Vin=18V, R1=1.5Ω, R2=3Ω, R3=4Ω, A=1.5 and B=0.5.

OpenStudy (anonymous):

Rth=3.6

OpenStudy (anonymous):

@joaoVitorMC If u got correct plz click the best response :D

OpenStudy (anonymous):

@benjo current through R3= (V1-(R1+R2)*(I1-I2))/(R1+R2+R3)

OpenStudy (anonymous):

@lucky12345 , please tell us how to find Rth for question 6 ????

OpenStudy (anonymous):

what are your values of q6

OpenStudy (anonymous):

Please Brother , tell us the formula for it .... I have reached very close , Rth = Vth/Isc ... But just let us know the expression/formula for 'Isc' , so that everyone else can do it ... Thanks

OpenStudy (anonymous):

its realy complicated tell me your values

OpenStudy (anonymous):

what is rth for v=15, r1=0.5, r2=1.5, r3=5, A=2, B=1.5

OpenStudy (anonymous):

@lucky12345 .....Please tell me how to calculate Rth.....my values are V in =27V , R 1 =5Ω , R 2 =7Ω , R 3 =12Ω , A=6 and B=0.1

OpenStudy (anonymous):

Please help with rth q6...only this part is left....

OpenStudy (anonymous):

how to calculate Rth . and its Isc

OpenStudy (anonymous):

ques no-4........can any one help me

OpenStudy (anonymous):

how do you do Q3?

OpenStudy (anonymous):

@epita tell me values of Q3

OpenStudy (anonymous):

Assuming that I=10A, Now assuming that I=−3A Finally, for the last two parts assume that I=5A.

OpenStudy (anonymous):

@epita I = 10 . . . Vo =2 I = -3 . . . Vo =-1 I = 5 . . . V1 =3.333 . .. . V0= 1.667

OpenStudy (anonymous):

Thanks a million!

OpenStudy (anonymous):

welcome

OpenStudy (anonymous):

I = 10 . . . Vo =2 I = -3 . . . Vo =-1 I = 1 . . . V1 =? . .. . V0= ? pls tell for i=1

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