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4|k + 5| > 8
Let N = {x|x is a multiple of 2} and P = {x|x is a multiple of 6}. Describe the intersection of N and P.
\[4\left| k+5 \right|>8\]\[\left| k+5 \right|>{8\over 4}\]Now because of absolute you have to account for positive and negative. So you solve for k in the following: \[k+5>2\]\[k+5<-2\]
What about the second question?
I'm not entirely sure, but the description of the intersection will be {x | x is a multiple of 2 and x is a multiple of 6} but when x is a multiple of 6 it is also a multiple of 2, so i guess the final set that results would just be {x | x is a multiple of 6} But I'm probably wrong on this one.
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