Question

a car traveling initially at 5.6 m/s accelerates uniformaly at the rate of +0.85 m/s2 for a distance of 244 m. What is its velocity at the end of the acceleration?

Answer 1

use:
\[V _{f}^{2} =V _{i}^{2} +2ad\]

Vf is final velocity
Vi is initial velocity
a is acceleration
and d is distance

Answer 2

i dont understand how to put the numbers in the equation.

Answer 3

"a car traveling initially at 5.6 m/s"
Vi = 5.6

"accelerates uniformaly (sic) at the rate of +0.85 m/s2 "
a=.85

"for a distance of 244 m"
d=244

"What is its velocity at the end of the acceleration?"
calculate Vf