Two stones are thrown simultaneously, one straight upward from the base of a cliff and the other straight downward from the top of the cliff. The height of the cliff is 6.46 m. The stones are thrown with the same speed of 8.07 m/s. Find the location (above the base of the cliff) of the point where the stones cross paths.

Too see what I had before I got stuck:
http://img842.imageshack.us/img842/5384/derpirstupid.jpg

Question

Two stones are thrown simultaneously, one straight upward from the base of a cliff and the other straight downward from the top of the cliff. The height of the cliff is 6.46 m. The stones are thrown with the same speed of 8.07 m/s. Find the location (above the base of the cliff) of the point where the stones cross paths.

Too see what I had before I got stuck:
http://img842.imageshack.us/img842/5384/derpirstupid.jpg

anonymous · Answer

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anonymous · Answer

@3psilon   I think if your top equation was 
$$y _{d} = x _{i} -V _{i}t -\frac{ 1 }{ 2 }at^2$$
it would work

3psilon · Answer

Yeah I see what I did wrong ! Thanks!