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Precalculus
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Write the trigonometric expression in terms of sine and cosine, and then simplify. csc2 x − cot2 x
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whats csc x in terms of sin x ?
thats what i do not know
csc x = 1/sin x
and cot x in terms of sin and cos is ?
cos/sin
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\[\csc^{2}x-\cot^{2}x=\frac{ 1 }{ \sin^{2}(x) }-\frac{ \cos^{2}(x) }{ sini^{2}(x) }\]\[=\frac{ 1-\cos^{2}(x) }{ \sin^{2}(x) }\]\[=\frac{ \sin^{2}(x) }{ \sin^{2}(x) }\]\[=1\]
that is correct, now just put both the formulas in the question, csc x = 1/ sin x and cot x = cos x / sin x
or u can see @Zekarias solution and ask if u don't understand any of thhe step...
so 1-cos^2x = sin ^2 x ?
yep
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thats from the identity \(\huge sin^2x+cos^2x = 1\)
ohh that makes sense. i remember now thanks
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