solve quadratic equation and tell some easy method to do it
\[3x ^{2} + 15x + 9 = 0 \]
i would recommend the formula
Compare your quadratic equation with \(ax^2+bx+c=0\) find a,b,c then the two roots of x are: \(\huge{x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}}\)
yes, that's easiest way i know
can't we go for middle term spilt?
check b^2-4ac, if it is perfect square, then we can split the middle term
b^2 - 4ac = 15^2 -4*3*9 =225-108 =117 is it right?
yes 117 is not a perfect square
so we can't split
I always recommend the formula, though factoring works if you need speed.
what is significance of this sign? \[\pm \]
that there are 2 roots, one considering + sign and other considering - sign
ok thanx so there is no simple way to this type of quadratic equation bcoz i don't like calculations?
you can use completing square method , then, but i won't say its easier....
what is that method?
3x^2+ 15x+ 9= 0 first make the co-efficient of x^2 as 1 divide the equation by 3, what u get ?
x^2 + 5x +3 = 0
now take the co-efficient of x, divide it by 2 and square it, what u get ?
25/4 x
just 25/4 , not x so add and subtract 25/4 in that equation
ok x^2 + 5x + 3 + 25/4 - 25/4 = 0
right , now write it like this : (x^2 + 5x + 25/4 )+ (3- 25/4) = 0 where (x^2...) is a perfect square
what about 3 - 25/4 ??
transfer that to other side (x^2 + 5x + 25/4 ) = 25/4-3
so u get (x+...)^2=.. take sqrt on both sides
so it become (x + 5/2)^2 = 13/4 sqrt of both sides x + 5/2 = sqrt ( 13/4)
when u take sqrt, u get 2 values, + or - x + 5/2 = \(\pm\)sqrt ( 13/4)
ok now i understood it well thanx so can i close it now?
yes, if u understand the steps and can do other similar problems, u can..
well thanx
welcome ^_^
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