Solving systems of equations through graphing x + 2y = 10, I got (10,0) 3x + 4y = 8, I got (8/3,2)... How exactly do I graph this...?
Is this your system of equations?\[\rm x +2y = 10\\ 3x + 4y = 8\]
If this is, you need to graph two different lines on the same graph plane.
The easiest way to graph a line is to find the x-intercept, then find the y-intercept, then pass a line through the two points.
So if you have a linear equation, say, 6x + 2y = 18, then: the x-intercept is (3,0) the y-intercept is (0,9) Mark these points and pass a line through them.
I know this... but how do I graph (8/3,2)?
That's neither the x-intercept nor the y-intercept. Let's go step-by-step, okay?
Oh so I messed up?
Yup.
So, can you tell me what the x-intercept for x + 2y = 10 is?
10
Yeah, actually (10,0) because x = 10 and y = 0. How about the y-intercept of x + 2y = 10?
5
(0,5) actually!
err sorry
So you have (10,0) and (0,5) mark them and pass a line thru.
You got one line, but you also gotta make a line for 3x + 4y = 8 right?
yes
Make the line for 3x + 4y = 8 on the SAME GRAPH PAPER.
so 3 * 0 + 4y = 8 Then 4y = 8 divide by 4 and I get y = 2 (0.2)
That's correct, and another point?
3x + 4 * 0 = 8 3x = 8 divide by 3 I get x = 8/3 (8/3, 0)
Very good! Now mark those points and pass a line thru.
How many lines do you have now?
one because I'm not sure how to graph (8/3,0)
lol
\[\rm \large {8 \over 3} = 2{2 \over 3}\]
So now do you get it?
yes
How many lines do you have now?
two
Great, and do those lines intersect?
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