Question

Algebra Help- I have to make a equation based upon a point and its slope. I will draw it out.

Answer 1

the equation I found for it is \[y=\frac{ 1 }{\sqrt{3} }-1\sqrt{3}x\]
How do I simplify this?

Answer 2

Which of the following points are on this slope?
A(-2,sqrt(3)),
B(0,1),
C(-1/3,2/sqrt(3))
D(-sqrt(3),2sqrt(3))

Answer 3

@ajprincess do you know how to solve this?

Answer 4

Point and its slope? Point-slope form!

Answer 5

@ParthKohli that part I did. But it gets ms confused algebretically solving with squareroots. How do I find all those points if they exists on the equation?

Answer 6

What is the question exactly?

Answer 7

after finding the equation, find if those points listed above are on that line or not.

Answer 8

Plug and play.

Answer 9

@parthkohli I tried, but it gets messed up. Can you help me step by step?

Answer 10

Let us substitute the first value and see.
(-2,sqrt(3)),
\(y=1/\sqrt3-\sqrt3x\)
\(=1/\sqrt3-\sqrt3(-2)\)
\( =1/\sqrt3+2\sqrt3\)
\(=(1+2\sqrt3(\sqrt3)/\sqrt3\)
\(=(1+2*3)/sqrt3\)
\(=(1+6)/\sqrt3\)
\(=7/\sqrt3\)
\(7/\sqrt3\ne\sqrt3\)
So this is nt a point.
Similarly can u chck the others too. @Comgroupmail?

Answer 11

Plug in C:
\[y = 1/\sqrt{3} - \sqrt{3}(-1/3) = 1/\sqrt{3} + 1/\sqrt{3} = 2/\sqrt{3}\]C is the answer. Do it this way and you will find all the others wrong