Question

Counterexample problem.. jus want to know if its right. Thanks!

Answer 1

x = 1

Answer 2

that looks right:)

Answer 3

thanks! :)

Answer 4

it's not right

Answer 5

what would happen if you plugged in x=1 ?
you get\[x^2\ge1\implies x\ge1\]\[1^2\ge1\implies1\ge1\]where is the falsehood here?

Answer 6

I agree with @TuringTest 1 does equal 1.

Answer 7

ohh yeah.. it wouldnt b false.

Answer 8

but its saying OR equal to

Answer 9

and it is equal, so it's true

Answer 10

@Emah yeahh thats true.. i dont see another answer that works

Answer 11

try each one individually

Answer 12

oh oops i sdidnt see the part that said couterexample:( sorry

Answer 13

ohh its okk

Answer 14

what do you get when you plug in x=2\[x^2\ge1\]\[x\ge1\]are both still true?

Answer 15

i get that its false

Answer 16

which part is false?

Answer 17

first part

Answer 18

\[2^2\ge1\]is not true you say?

Answer 19

Im confused

Answer 20

we need to find an example where the first part is true, and the second part is false to disprove the statement

Answer 21

\[2^2=4\]and four is greater than one, so \[x^2\ge1\]is true for x=2

Answer 22

what about the other part, is\[2\ge1\]?

Answer 23

its true because 2 is greater tha 1

Answer 24

right, so both statements are true for x=2, so this is not a counterexample

Answer 25

what about for x=-3
is\[x^2\ge1\]and is\[x\ge1\]?

Answer 26

first one is 9 > 1 (true)
second one is 3 > 1 (true too)

Answer 27

so than its 1/4 (: