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solve for t e^(t^(2))=25
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e^t^2=25
take the base e log of both sides \[\ln(e^a) = a\] so then t^2 = ln(25) I'll let you finish it.
did your lecture teach you ln also
natural log
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No, section 6.1 & 6.2 are on the test this Monday and he didnt teach us any of this
@campbell_st Do i square root both sides?
ln works like the log,remeber for logs the base is ten \[\log a=\log_{10}a\] e a constant is a special base with a special log called the natural log so use it the same way you use logs
that would be the next step
\[t=\pm \sqrt{\ln 25}\]
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hmm... thats what i did but WileyPLUS is showing that i got it incorrect
...nevermind I had to change it up a bit thanks again
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