Mathematics
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OpenStudy (anonymous):
Calculate the derivative using the appropriate rule or combination of rules
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OpenStudy (anonymous):
\[\frac{ 4x ^{4}-x ^{2}+2 }{ \sqrt{x} }\]
OpenStudy (anonymous):
i have this done so far:
\[\frac{ \sqrt{x}(16x ^{3}-2x)-\frac{ 4x ^{4}-x ^{2}+2 }{ 2\sqrt{x} } }{ x }\]
OpenStudy (anonymous):
or is there a simplier way to do this one?
OpenStudy (anonymous):
looks fine
OpenStudy (anonymous):
find a CD in the numerator...
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OpenStudy (anonymous):
now im a little confused as to how to continue.. not sure how to simplfy this one.
OpenStudy (anonymous):
2 root x would be the cd
OpenStudy (anonymous):
\[ \frac{2x(16x^3−2x)−(4x^4−x^2+2) }{ 2\sqrt{x} }\]
OpenStudy (anonymous):
all over x
OpenStudy (anonymous):
so what you wrote there all over x.
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OpenStudy (anonymous):
yes, that's just the numerator...
OpenStudy (anonymous):
so can i multiply the x on the very bottom by its reciprocal to get 2x root x on the bottom?
OpenStudy (anonymous):
yes:)
OpenStudy (anonymous):
then my 2x on the top and botton will cancel right?
OpenStudy (anonymous):
no..
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OpenStudy (anonymous):
oh pellet lol
OpenStudy (anonymous):
lol s -- h -- i --- t **
OpenStudy (anonymous):
distribute the 2x and you'll have some like terms to combine..
OpenStudy (anonymous):
put the 2x into 16x^3-2x?
then i can factor the numerator?
OpenStudy (anonymous):
you may be able to factor it.. combine like terms first
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OpenStudy (anonymous):
doesn't look factorable though...
OpenStudy (anonymous):
i got:
28x^4+3x^2-2x/2xrootx
OpenStudy (anonymous):
28x^4 -3x^2 -2
OpenStudy (anonymous):
right no x at the end there