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Mathematics 19 Online
OpenStudy (anonymous):

Calculate the derivative using the appropriate rule or combination of rules

OpenStudy (anonymous):

\[\frac{ 4x ^{4}-x ^{2}+2 }{ \sqrt{x} }\]

OpenStudy (anonymous):

i have this done so far: \[\frac{ \sqrt{x}(16x ^{3}-2x)-\frac{ 4x ^{4}-x ^{2}+2 }{ 2\sqrt{x} } }{ x }\]

OpenStudy (anonymous):

or is there a simplier way to do this one?

OpenStudy (anonymous):

looks fine

OpenStudy (anonymous):

find a CD in the numerator...

OpenStudy (anonymous):

now im a little confused as to how to continue.. not sure how to simplfy this one.

OpenStudy (anonymous):

2 root x would be the cd

OpenStudy (anonymous):

\[ \frac{2x(16x^3−2x)−(4x^4−x^2+2) }{ 2\sqrt{x} }\]

OpenStudy (anonymous):

all over x

OpenStudy (anonymous):

so what you wrote there all over x.

OpenStudy (anonymous):

yes, that's just the numerator...

OpenStudy (anonymous):

so can i multiply the x on the very bottom by its reciprocal to get 2x root x on the bottom?

OpenStudy (anonymous):

yes:)

OpenStudy (anonymous):

then my 2x on the top and botton will cancel right?

OpenStudy (anonymous):

no..

OpenStudy (anonymous):

oh pellet lol

OpenStudy (anonymous):

lol s -- h -- i --- t **

OpenStudy (anonymous):

distribute the 2x and you'll have some like terms to combine..

OpenStudy (anonymous):

put the 2x into 16x^3-2x? then i can factor the numerator?

OpenStudy (anonymous):

you may be able to factor it.. combine like terms first

OpenStudy (anonymous):

doesn't look factorable though...

OpenStudy (anonymous):

i got: 28x^4+3x^2-2x/2xrootx

OpenStudy (anonymous):

28x^4 -3x^2 -2

OpenStudy (anonymous):

right no x at the end there

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