Question

There are two rows,one behind other,of 5 chairs each.Five couples are to be seated,
number of arrangements such that no husband sits in front or behind his wife

Answer 1

impossibruuu level:asian

Answer 2

:(

Answer 3

The permutations theorem dealing with classes of different things could apply here.
If n given things can be divided into c classes of alike things differing from class to class, then the number of permutations of these things taken all at a time is:
\[\frac{n!}{n _{1}!n _{2}!....n _{c}!}where(n _{1}+n _{2}+.....+n _{c}=n)\]
The classes in the question are the 5 different couples. So the number of seating arrangements is:
\[\frac{10!}{2!2!2!2!2!}\]

Answer 4

ans=wrong

Answer 5

it gives 113400 butits190080

Answer 6

told u imposssibru lvl: stephen hawking

Answer 7

lol