Question

This is my equation and I am having trouble figuring it out... 10(x+y) to the 0 power.. can someone help?

Answer 1

Okay, so do you know what anything to the 0 power is?

Answer 2

yes it is 1

Answer 3

anything to the power of zero is 1, unless the base is zero. so when ever x+y not equal to zero. it is 1

Answer 4

okay so from there my equation would be 10(1)?

Answer 5

depends if you want \[10(x+y)^{0}\] it is 10(1), or if you whole power(including 10 also) it is 1

Answer 6

okay my equation is 10(x+y)^{0}

Answer 7

by the way you have written the equation, it seems 10 is excluded from the zero power.so it is 10..

Answer 8

so i would not do this :
10(x+y)^{0}
10(x ^{0}+y ^{0})
which would be:
10(1+1)
and then:
10(2)
and then 20

Answer 9

are you still there?

Answer 10

hey sorry, that is wrong

Answer 11

my answer?

Answer 12

see you can not take the power inside like that, it should be \[(x+y)^{0}\]

Answer 13

which is 1, so 10*1 is 10

Answer 14

if the question is \[(10(x+y))^{0}\] then it is 1

Answer 15

okay I understand now, shoot you wanna come be my teacher cause my teacher isnt any good.. lol do you have time to help me with few more?

Answer 16

yah

Answer 17

sweet! okay here we go!

Answer 18

simplify. write the answer using positive exponents only.

Answer 19

\[(8x ^{-4}y ^{-2}z ^{3}/2xy ^{-2}z ^{-3})^{-1}\]

Answer 20

ok first think \[(x ^{a})^{b} =x ^{ab}\]

Answer 21

exponents are multiplied here, correct

Answer 22

\[(xy)^{a} = x ^{a}*y ^{a}\]

Answer 23

yah perfect, multiply the exponents

Answer 24

okay give me a second im gonna post up my work.

Answer 25

Okay so if we break everything up into peices.. (excuse the spelling im not an english major I PROMISE :-) )

Answer 26

lol.. neither me

Answer 27

we have:
\[8^{1*-1}=-8\]
\[x ^{-4*-1}=x ^{4}\]
\[y ^{-2*-1}=y ^{2}\]
\[z ^{3*-1} = z ^{-3}\]

divided by:
\[2^{1*-1}=-2\]
\[x ^{1*-1}=x ^{-1}\]
\[y ^{-2*-1}=y ^{2}\]
\[z ^{-3*-1}=z ^{3}\]

so in the end we have
\[-8x ^{4}y ^{2}z ^{-3}\div-2x ^{-1}y ^{2}z ^{3}\]

Answer 28

\[8^{-1}= \frac{ 1 }{ 8 }\]

Answer 29

and from there we move them accordingly such as.. idk if i am right i am just throwing out what i think...

Answer 30

o okay now im lost haha

Answer 31

okay i will tell you step wise..

Answer 32

nvm i see where u got that

Answer 33

everything you have done is correct except -2 and -8, they are 1/8 and 1/2

Answer 34

okay now so to eliminate the negative exponents dont I just subtract then flip them except for the y's because they equal each other out right.. because \[y ^{2}-y ^{2}=0\] correct?

Answer 35

\[\frac{ 1 }{ x ^{a} } = x ^{-a}\]

Answer 36

correct.. so in the end my equation minus the 8&2 should be this:

\[x ^{5}\div z ^{6}\]

Answer 37

right?

Answer 38

\[\frac{ x ^{4} }{ x ^{-1} } = x ^{4-(-1)}\]

Answer 39

= \[x ^{5}\]

Answer 40

awesome.. thats it

Answer 41

what about 8 &2

Answer 42

do they flip spots as well to make them even

Answer 43

just 8*x^5/2*z^6 =4*x^5/z^6

Answer 44

huh

Answer 45

8*?

Answer 46

2*?

Answer 47

sorry my bad, x^5/4*z^6

Answer 48

because 2/8 = 1/4

Answer 49

\[\frac{ x ^{5} }{ 4*z ^{6} }\]

Answer 50

yes

Answer 51

okay not to be nosey or anything but what is ur name?

Answer 52

charan, and you??

Answer 53

paige.. r u a b or g

Answer 54

hehe.. b

Answer 55

how old
im a g

Answer 56

20 , which class r u in??

Answer 57

im not trying to freak you out sorry.. i am 21 almost 22 and i swear if you are younger than me i feel like a retard

Answer 58

i go to lone star college so my math is called 0308 its like 1 or 2 levels down from college math but not the very first one.. if that makes any sense

Answer 59

hehe.. nothing there to feel anything. i am sure you are good at something else, and yah im nt freaked out :-)

Answer 60

lol... i m usually pretty good at math... i just missed like a whole week of classes.. so I am so far behind and I have a test when I get back and I am already failing this class cause my teacher is a feather.. and I have to PASS!!! if I dont they take my financial aid and i will lose my extra money for my house and I have a 6 mnth old daughter I cant afford to lose my house.. but anyways.. so can u still help me with some more since you are super smart.. and by the way your user name is a total lie.. your not a loser your freaking smart!

Answer 61

hehe.. im not super smart. yah i can help you.

Answer 62

you rock!! and well your smarter than me that is for sure... i wish this board thing worked better...

Answer 63

okay i am doing something relly quick so if i lose you please come find me again cause I DESPERATLY need help lol

Answer 64

okay sorry im back i had to fix my wireless

Answer 65

whats your next question?

Answer 66

okay hold on let me get it.. I am going through this review trying to figure out which ones i know and which ones I dont.. where r u from.. if you dont mind me asking while i find the next problem

Answer 67

im from tomball/cypress area i dont know if you know where that is but it is in texas

Answer 68

okay next problem...

Answer 69

ok, im from india.

Answer 70

ooo okyy.. wow so far away.. what time is it there?

Answer 71

9pm

Answer 72

wait hold on we did this on i forgot to correct it hold please i do have more problems tho

Answer 73

okay got it number 5...
Directions:
Simplify and write positive exponents only.
the problem is:
\[7^{-1}+3^{-1}\]

Answer 74

\[\frac{ 1 }{ 7 } +\frac{ 1 }{ 3 } = \] \[\frac{ 10^{1} }{ 21^{1} }\]

Answer 75

okay so its like the other problem we did

Answer 76

yah.. i dont think any more simplification can be done

Answer 77

no it cant..

Answer 78

okay you ready for another one.. these next like 2 or 3 im gonna give you the problem and the answer and can u tell me if they r right please?

Answer 79

ok

Answer 80

okay the first one goes like this:
directions:
Add
Problem:
\[(3x ^{2}y-4xy+7)+(-2x ^{2}y+12xy-9)\]
Answer:
\[x ^{2}y+8xy-2\]

Answer 81

correct answer

Answer 82

Sweet.. Okay next.. Unless you have to go.. i dont want to keep you up.. cause its like 11 am here

Answer 83

i wnt sleep this early, you can ask your questions

Answer 84

Okay, your a life saver, just let me know if you need to go!!

Answer 85

ok

Answer 86

okay here is another for you...
directions:
multiply
question:
\[(x-6)(-5x-9)\]
Answer:
\[-5x ^{2}+21x+54\]

Question:
\[(-3x ^{2}+8y)(-3x ^{2}-7y)\]
Answer:
\[9x ^{4}-3x ^{2}y-56y ^{2}\]

Answer 87

perfect.. both are correct :)

Answer 88

Oky as you are grading me I am working the problems.. I am trying to go as fast as i can.. but okay I am stuck again..
Directions: Multiply
Question:
(x+1/9)(x-1/9)
Answer:
I am Lost.. I got
\[x ^{2}-1/81\]

Answer 89

thats it :)

Answer 90

but the -1/81 the doesnt make sense i guess to me

Answer 91

no.. why do you feel so, (a+b)*(a-b) = \[a ^{2}-b ^{2}\]

Answer 92

okay.. i trust you i guess it just looks weird to me but your the math genius so i shall not argue with u

Answer 93

this is too much, that equation i studied in my 6th class :-) syllabus in India and US are right

Answer 94

Okay I am pretty sure this one is right but I just want to double check...
Directions:
Multiply
Question:
\[(5xy ^{2}+6x)(5xy ^{2}-6x)\]
Answer:
\[25x ^{2}y ^{4}-36x ^{2}\]

Answer 95

right :-)

Answer 96

you studied this in 6TH GRADE!!!?????

Answer 97

yah 6th or 7th grade :)

Answer 98

holy pellet.. i feel really dumb now.. why do yall want to come over here yll education system is much better than ours it seems.. yall r way more advanced... i dont mean that in a racial way at all i swear..