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Suppose you are given that tan(theta)=3. The hypotenuse=9, so find area of triangle. Please Help!
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\[a ^{2}+3a ^{2}=81\]\[b=3a\]
that will find your sides a,b and then you can get the area.
\[\tan \theta = \frac{ opposite }{ adjacent } = 3\]if we let opposite be b and adjacent be a we have \[\frac{ b }{ a }=3=\frac{ 3a }{ a }\]
That is how I arrived at my equation above. now solve for a, then you can get b, therefore the area
Are you good from here?
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