OpenStudy (anonymous):

Suppose you are given that tan(theta)=3. The hypotenuse=9, so find area of triangle. Please Help!

5 years ago
OpenStudy (anonymous):

thx @hartnn

5 years ago
OpenStudy (anonymous):

|dw:1351353351891:dw|

5 years ago
OpenStudy (anonymous):

\[h=9\text{ Sin}[\text{ArcTan}[3]]\text{=}\frac{27}{\sqrt{10}}\]\[b\text{ = }9\text{ Cos}[\text{ArcTan}[3]]\text{=}\frac{9}{\sqrt{10}}\]\[A=\frac{1}{2}\frac{9}{\sqrt{10}} \frac{27}{\sqrt{10}}=\frac{243}{20}=12.15 \]

5 years ago
Similar Questions: