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OpenStudy (anonymous):
Suppose you are given that tan(theta)=3. The hypotenuse=9, so find area of triangle. Please Help!
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OpenStudy (anonymous):
thx @hartnn
OpenStudy (anonymous):
|dw:1351353351891:dw|
OpenStudy (anonymous):
\[h=9\text{ Sin}[\text{ArcTan}[3]]\text{=}\frac{27}{\sqrt{10}}\]\[b\text{ = }9\text{ Cos}[\text{ArcTan}[3]]\text{=}\frac{9}{\sqrt{10}}\]\[A=\frac{1}{2}\frac{9}{\sqrt{10}} \frac{27}{\sqrt{10}}=\frac{243}{20}=12.15 \]
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