0 ( 4x2 - 2) 2 ℮ 2 x dx
the parser work for latex, not html
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actually its an integral ,i copy pasted it from word
looks like you are trying to integrate (4x^2-2)^2 , from 2 to 0
might wanna copy and paste it into notepad first
there is an also exp(-x^2) with limits o to infinity
the latex for this would be close to: ``` \[\int_{2}^{0}(4x^2-2)^2~dx\] ```
\[\int_{2}^{0}(4x^2-2)^2~dx\] but im not to sure where to put the exp() stuff
in multiplication and 0 is lower and infinity is upper limit
``` \[\int_{0}^{\infty}(4x^2-2)^2~exp(-x^2)~dx\] ``` \[\int_{0}^{\infty}(4x^2-2)^2~exp(-x^2)~dx\] like this?
yes thats right !! thanks a loti am sorry i dont use latex and i m not familiar but i am thankful to u for helping.i also need help to solve it lol...
my first thought is by parts, that poly will go to zero after a few turns, and we can always integrate the exp which is just another notation for e^(-x^2)
i think it is an improper integral and may be somr trick is involved .may be something related to complex integration ..may be jordan lemma but i am not able to do it...;(
\[\begin{matrix} &&e^{-x^2}\\ +&(4x^2-2)^2&-2xe^{-x^2}\\ -&2(4x^2-2)(8x)&4x^2e^{-x^2}+-2e^{-x^2}\\ +&16(4x^2-2)+16x(8x)&gets~messier\\ -&192x^2-32&"\\ +&192(2)x&"\\ -&19(2)&"\\ &0&--\\ \end{matrix}\]
yeah, im not to useful with complex or jordan lemma stuff. not enough practice or exposure to it
its answer is not zero i also dont know the answer but its between the 4 choices 4pi,8 sqrt pi , 4 sqrt pi , 8 pi.
if anything, we could expand the poly out, and run it out in pieces
do you know what the trig equivalent of e^-x^2 would be?
i knw exp(iq)=cosq+i sinq so something similar to that may be
no it will involve sinh and cosh yes
the hs look more righter to me
if it helps to double check to make sure youre on the right track; the answer should be 4 sqrt(pi) http://www.wolframalpha.com/input/?i=integrate+%284x%5E2-2%29%5E2+e%5E%28-x%5E2%29+dx+from+0+to+inf
did u use mathematica for it ?
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