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Inverse function of y = 2x + ln(x)
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And I don't know what the W lambert function is...
you have to switch x and y in the equation and then solve for y
y = 2x + ln(x) Interchange x and y and re-solve for y. x = 2y + ln(y) ==> e^x = e^[2y + ln(y)] ==> e^x = e^(2y)*e^[ln(y)] ==> e^x = y*e^(2y) ==> 2*e^x = 2y*e^(2y) ==> W(2*e^x) = 2y <== y = x*e^x <=> x = W(y) ==> W(2*e^x)/2 = y Therefore, the inverse is: f^-1(x) = W(2*e^x)/2
@CliffSedge
Gimme a sec. I lost my pencil.
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That is an answer off yahoo answers... Is this so called w-function needed?
lol..
I'm not sure if it's needed, but it can be used.
|dw:1351379674787:dw|
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