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Mathematics 20 Online
OpenStudy (anonymous):

Can someone please explain the chain rule to me?

OpenStudy (anonymous):

The chain rule lets you take derivatives of functions more complicated than the basic ones you've been shown. For instance you can probably take the derivative of \[y=x^6\to y^{\prime}=6x^5\] But what do you do when you have \[y=(5x^3+3x^2+23)^6\]

OpenStudy (anonymous):

The chain rule allows you to substitute a function of x for the interior of that function above \[y=(5x^3+3x^2+23)^6\to (u(x))^6\] Because we know that \[\frac{d}{du} u^6=6u^5\]

OpenStudy (jusaquikie):

it gets confusing so i'm going to give you the way i understand it best. let's say we have \[\sqrt{x^2+1}\] we can re write this as \[(x+1)^\frac{ 1 }{ 2 }\] first we take the derivitive of the outer function which is \[\sqrt{?}\] so that is \[\frac{ 1 }{2 }(the stuff)^{\frac{ -1 }{ 2 }}\] or \[\frac{ 1 }{2 }(x+1)^{\frac{ -1 }{ 2 }}\] then we multiply that by the derivitave of the stuff \[\frac{ 1 }{2 }(x+1)^{\frac{ -1 }{ 2 }} * 1\]

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