Question

What is the relative maximum and minimum of the function?
f(x)= 2x^3 + x^2 – 11x


The relative maximum is at (–1.53, 8.3) and the relative minimum is at (1.2, –12.01).

The relative maximum is at (–1.53, 12.01) and the relative minimum is at (1.2, –8.3).

The relative maximum is at (–1.2, 8.3) and the relative minimum is at (1.53, –12.01).

The relative maximum is at (–1.2, 12.01) and the relative minimum is at (1.53, –8.3).

Answer 1

\[f(x)= 2x^3 + x^2 – 11x \]
\[f'(x)=6x^2+2x-11\] set equal to zero and solve
you know it looks like this

so the smallest zero will be a relative max, largest a relative min

Answer 2

Im still confused ?

Answer 3

is this a calc class?

Answer 4

algebra 2 -______-

Answer 5

of so i can explain
if not, then i cannot

Answer 6

do you have a graph to work with? i have no idea how to do this without using calculus

Answer 7

nope :( , thats all it gave me up there .

Answer 8

maybe a graphing calculator
otherwise you need calculus

Answer 9

i dont have a graphing calc . i have a TI-30 -____- lol

Answer 10

then look at this
http://www.wolframalpha.com/input/?i=+2x^3+%2B+x^2+%E2%80%93+11x

Answer 11

scroll down to "local max" and "local min" and then click on "approximate form" to get your answer as a decimal

Answer 12

thank you . that website helped alottt ! (;

Answer 13

yw

Answer 14

it is a good one, and easy enough to use once you figure out the syntax