Question

Solve Triangle FGH. Round to the nearest degree.
Picture attached!

Answer 1

@jim_thompson5910 can you help me please?

Answer 2

sorry for getting to you so late, you can use the law of cosines to solve for each angle

Answer 3

so for instance, let's say we're solving for angle F (ie finding the measure of angle F)



The law of cosines is a^2=b^2+c^2-2bc*cos(A)



where 'a', b and c are the sides of the triangle and angle A is opposite side 'a'.



To find angle F, we do this...



a^2=b^2+c^2-2bc*cos(A)



(6.3)^2=(5.6)^2+(5.8)^2-2(5.6)(5.8)*cos(F)



39.69=(5.6)^2+(5.8)^2-2(5.6)(5.8)*cos(F)



39.69=31.36+(5.8)^2-2(5.6)(5.8)*cos(F)



39.69=31.36+33.64-2(5.6)(5.8)*cos(F)



39.69=31.36+33.64-11.2(5.8)*cos(F)



39.69=31.36+33.64-64.96*cos(F)



39.69=65-64.96*cos(F)



39.69-65=-64.96*cos(F)



-25.31=-64.96*cos(F)



(-25.31)/(-64.96)=cos(F)



0.389624384236453=cos(F)



cos(F)=0.389624384236453



F=arccos(0.389624384236453)



F=67.0688704863168



So the angle F is roughly 67.0688704863168 degrees

Answer 4

It's a lot I know, but hopefully you can go through it step by step without too much trouble and make sense of it all

You can then use this idea to find angles G and H.