Can someone help me find the inequailty that belongs to this graph?!?

Question

anonymous · Answer

attachment

anonymous · Answer

@freewilly922 Its asking me to write and Inequality for the graph...(:

anonymous · Answer

*an

anonymous · Answer

the easiest way to find this inequality is to graph the function.  since it looks similar to f(x) = |x|  you can just transpose the graph.

anonymous · Answer

Got it. 
Ok this is going to be an inequality of the form 
$$|x-p|+q\le y$$
And we know this because the slope of the lines in the graph are 1 and -1. So in general
we want to find (p,q) which is the vertex of the graph (the point place)

anonymous · Answer

So the point coordiantes is up one of five right?? where do I go from there

anonymous · Answer

(1,5)

anonymous · Answer

what do you have to do the graph of f(x) = |x| to get it to move +5 on the x axis and +1 on the y axis?

anonymous · Answer

Ok we what I meant by the slope part is that there isn't a pre factor by the absolute value bars that would squish or expand. 
up 1 would be q=1 and right 5 would be p=5 and then insert them into the equation.

anonymous · Answer

@Nameless has the right way of introducing the linear transformation though. I wish I explained it that way from the start....

anonymous · Answer

Ix-5I + 1 < y like that now do i solve that

anonymous · Answer

You don't. The question asked for the inequality for the graph. That's it:) I would suggest you understand the movements of the parent function y=|x-p|+q though...

anonymous · Answer

and it might be $$\le$$ not <