Question

Factor The expression completely
-9abc-9ac^2+6bc+6c^2

Answer 1

Well first you can factor out \(3c\) from them, since they all have that:
\[-9abc-9ac^2+6bc+6c^2\]\[3c(-3ab-3ac+2b+2c)\]Then you want to factor out that \(-3a\)
\[3c(-3a(b+c)+2b+2c)\]Then the 2 can be factored:
\[3c(-3a(b+c)+2(b+c))\]Then factor out the \(b+c\):
\[3c(-3a+2)(b+c)\]

Answer 2

Thank u soo much