Question

please check that my derivative is right
function: 2x^2-10xp+50p^2=6200
trying to get (d/dt)
I have 4x(dx/dt)-10x(dp/dt)-10(dx/dt)p+100(dp/dt)=0
am i going wrong somewhere? If so please help!

Answer 1

Looks perfectly fine to me.

Answer 2

ok thank you

Answer 3

at last there should be 100p(dp/dt)

Answer 4

ur right! maybe that's why its not working out for me..

Answer 5

Yes, there needs to be a p in there, sorry I overlooked it. I was focusing on those two middle terms being correct and figured you got the other two right.

Answer 6

@darkmare
did you got right answer now?

Answer 7

no.... :(

Answer 8

are you having any problem?

Answer 9

This is the question i'm working on:
A price p (in dollars) and demand x for a product are related by
2x^2-10xp+50p^2=6200
If the price is increasing at a rate of 2 dollars per month when the price is 10 dollars, find the rate of change of the demand.

Answer 10

i thought that my derivative was wrong and thats why i wasnt getting the right answer

Answer 11

for this you have to calculate dp/dt

Answer 12

why dp/dt?

Answer 13

bcoz you have given dp/dt = 2

Answer 14

and calulate dx/dt

Answer 15

so i take the derivative for dp/dt to find dx/dt?

Answer 16

4x(dx/dt)-10x(dp/dt)-10(dx/dt)p+100p(dp/dt)=0
dp/dt = 2
dx/dt = calculate it

Answer 17

so then i'd get dx/dt= (-2000+20x)/(4x+100)
is that right so far?

Answer 18

when i solve the original equation for x i get x= -60 and +10 how would i know which one to use?

Answer 19

product is always +ve
use + 10

Answer 20

grrr why is this not working for me....