Question

Is the cotan(theta) function the same as tan^-1(theta)?

Answer 1

\[\cot \theta = \frac{ 1 }{ \tan \theta }\]

Answer 2

So that's a yes? If I'm entering it into my calculator (there is no cot function), I enter\[\cot(\theta) = \tan^{-1}(\theta)\]

Answer 3

you can't write it as
\[\tan ^{-1} \theta \]

Answer 4

Isn't that the same thing...? Doesn't:
\[\frac{ 1 }{ \tan(\theta) } = \tan ^{-1}(\theta)\]

Answer 5

no my friend

Answer 6

:( okay. Thanks

Answer 7

nope. to find cot(theta), do this: 1/(tan(theta))

Answer 8

when we take tan function from one side of equality to other then we write tan^-1

Answer 9

So you use tan^-1 in something like... To solve for x if tan(x)=a, then x=tan^-1(a)

Answer 10

yes you are right

Answer 11

Thank you :)

Answer 12

welcome

Answer 13

Can you say\[\csc ^{4}(\theta) = \frac{ 1 }{ \sin ^{4}(\theta) }\]

Answer 14

yep. in calculator, that would be: 1/(sin(theta))^4

Answer 15

-1 is a special case in trigonometric functions..

-1 corresponds to inverse function..
thus for 1/sin, we use cosec and likewise..

Answer 16

Thanks I get it now :)

Answer 17

hmm,,glad you do!