Question

Need a double check:

Answer 1

\[\int\limits_{1}^{3} \frac{ 1 }{ x }dx:\]

My answer is log(3)-log(1)= 0.477121254...

Answer 2

Is this the correct assessment?

Answer 3

use naural logarithm. ln(3)-ln(1)

Answer 4

Ahh thanks, it's now 1.098612289

Answer 5

yep

Answer 6

Isn't it ln(1)-ln(3)?

Answer 7

nope. top minus bottom

Answer 8

I also have this one:

Answer 9

\[\int\limits_{-3}^{-1} \frac{ 1 }{ x }dx\]
Which when I do ln(-3)-ln(-1) gives me Math error :S

Answer 10

errr ln(-1)-ln(-3) I mean.

Answer 11

use this identity: lnA-lnB=ln(A/B)
thus ln(-1)-ln(-3)=ln(-1/-3)=ln(1/3)=-1.0986

Answer 12

That makes sense, I forgot about identities, felt like I was missing something. Thanks! :)

Answer 13

np