Complex number help
The complex number w is defined by w = 2 + i.
Shade on an Argand diagram the region whose points represent the complex numbers z which
satisfy
|z − w^2| ≤ |w^2|.
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OpenStudy (calculator):
I already found the value of w, that is 3+4i but how to plot it
OpenStudy (calculator):
I mean w^2 is 3+4i
OpenStudy (anonymous):
l w^2 l=?
OpenStudy (calculator):
|w^2|=5
OpenStudy (calculator):
oh so you just substitute in?
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OpenStudy (anonymous):
so u have l z- (3+4i) l <= 5
OpenStudy (anonymous):
fine?
OpenStudy (calculator):
why its not
|z − 5| ≤ |5|.
OpenStudy (calculator):
oh i get it
OpenStudy (anonymous):
its not |Z-|w||
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OpenStudy (calculator):
yes thanks
OpenStudy (anonymous):
inside the modulus its w^2 ....not l w^2 l
OpenStudy (anonymous):
so how u'll plot this
l z- (3+4i) l <= 5?
OpenStudy (anonymous):
circle!
OpenStudy (calculator):
im not sure
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OpenStudy (anonymous):
okay...z is a complex no...put z= x+iy
OpenStudy (calculator):
i get |z+7-24i|<5
OpenStudy (anonymous):
w=2+i then w^2=?
u only told w^2=3+4i
OpenStudy (anonymous):
then how it's 7-24 i?
OpenStudy (anonymous):
u have squared again....right?
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OpenStudy (anonymous):
l z- (3+4i) l <= 5
OpenStudy (calculator):
yes from here i square it
|z+7-24i|<5
(z+7-24i)^2<25
OpenStudy (anonymous):
on LHS u have l z-w^2 l
and w=2+i
OpenStudy (anonymous):
let w^2=3+4i, Z=x+yi
.: |(x+yi)-(3+4i)|<=5 |(x-3)+(y-4)i|<=5
OpenStudy (anonymous):
\[\sqrt{(x-3)^2+(y-4)^2} <=5\]
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OpenStudy (calculator):
ok i got \[\sqrt{(x-3)^2+(y-4)^2} <=5\]
OpenStudy (anonymous):
yes.. keep going
OpenStudy (calculator):
\[(x-3)^2+(y-4)^2 <=25\]
OpenStudy (anonymous):
yup so (x=3)^2+(y-4)^2<=5^2 centre with centre (3,4) radius 5
OpenStudy (anonymous):
but u only want the points <= the radius
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OpenStudy (calculator):
so we can just use
\[\sqrt{(x-3)^2+(y-4)^2} <=5\]
to find the center and radius?
OpenStudy (anonymous):
hm? gneeral form of circle is (x-h)^2+(y-k)^2=r^2 where centre at (h,k) and radius of r
OpenStudy (calculator):
ok
OpenStudy (anonymous):
do u get
OpenStudy (calculator):
yes
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OpenStudy (calculator):
but now i need to draw the circle
OpenStudy (anonymous):
btw |z − w^2| ≤ |w^2| you dont need to do algebraically if u dont want to..
if you have |Z1-Z2|=k, that means that the distance from Z1 to Z2 has to equal k.. in this case the distance of Z from the point w^2 has to be constant |w^2|.. you can do just like that
OpenStudy (anonymous):
so draw the circle?? midpoint at (3,4)
OpenStudy (anonymous):
how about this.. think of it as.. the distance of Z(x,y) from the point 3+4i has to be 5
OpenStudy (calculator):
|dw:1351515619965:dw|
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