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Mathematics 17 Online
OpenStudy (calculator):

Complex number help The complex number w is defined by w = 2 + i. Shade on an Argand diagram the region whose points represent the complex numbers z which satisfy |z − w^2| ≤ |w^2|.

OpenStudy (calculator):

I already found the value of w, that is 3+4i but how to plot it

OpenStudy (calculator):

I mean w^2 is 3+4i

OpenStudy (anonymous):

l w^2 l=?

OpenStudy (calculator):

|w^2|=5

OpenStudy (calculator):

oh so you just substitute in?

OpenStudy (anonymous):

so u have l z- (3+4i) l <= 5

OpenStudy (anonymous):

fine?

OpenStudy (calculator):

why its not |z − 5| ≤ |5|.

OpenStudy (calculator):

oh i get it

OpenStudy (anonymous):

its not |Z-|w||

OpenStudy (calculator):

yes thanks

OpenStudy (anonymous):

inside the modulus its w^2 ....not l w^2 l

OpenStudy (anonymous):

so how u'll plot this l z- (3+4i) l <= 5?

OpenStudy (anonymous):

circle!

OpenStudy (calculator):

im not sure

OpenStudy (anonymous):

okay...z is a complex no...put z= x+iy

OpenStudy (calculator):

i get |z+7-24i|<5

OpenStudy (anonymous):

w=2+i then w^2=? u only told w^2=3+4i

OpenStudy (anonymous):

then how it's 7-24 i?

OpenStudy (anonymous):

u have squared again....right?

OpenStudy (anonymous):

l z- (3+4i) l <= 5

OpenStudy (calculator):

yes from here i square it |z+7-24i|<5 (z+7-24i)^2<25

OpenStudy (anonymous):

on LHS u have l z-w^2 l and w=2+i

OpenStudy (anonymous):

let w^2=3+4i, Z=x+yi .: |(x+yi)-(3+4i)|<=5 |(x-3)+(y-4)i|<=5

OpenStudy (anonymous):

\[\sqrt{(x-3)^2+(y-4)^2} <=5\]

OpenStudy (anonymous):

good??

OpenStudy (anonymous):

LOL hi!!

OpenStudy (anonymous):

@Calculator do u get it?

OpenStudy (calculator):

wait

OpenStudy (calculator):

ok i got \[\sqrt{(x-3)^2+(y-4)^2} <=5\]

OpenStudy (anonymous):

yes.. keep going

OpenStudy (calculator):

\[(x-3)^2+(y-4)^2 <=25\]

OpenStudy (anonymous):

yup so (x=3)^2+(y-4)^2<=5^2 centre with centre (3,4) radius 5

OpenStudy (anonymous):

but u only want the points <= the radius

OpenStudy (calculator):

so we can just use \[\sqrt{(x-3)^2+(y-4)^2} <=5\] to find the center and radius?

OpenStudy (anonymous):

hm? gneeral form of circle is (x-h)^2+(y-k)^2=r^2 where centre at (h,k) and radius of r

OpenStudy (calculator):

ok

OpenStudy (anonymous):

do u get

OpenStudy (calculator):

yes

OpenStudy (calculator):

but now i need to draw the circle

OpenStudy (anonymous):

btw |z − w^2| ≤ |w^2| you dont need to do algebraically if u dont want to.. if you have |Z1-Z2|=k, that means that the distance from Z1 to Z2 has to equal k.. in this case the distance of Z from the point w^2 has to be constant |w^2|.. you can do just like that

OpenStudy (anonymous):

so draw the circle?? midpoint at (3,4)

OpenStudy (anonymous):

how about this.. think of it as.. the distance of Z(x,y) from the point 3+4i has to be 5

OpenStudy (calculator):

|dw:1351515619965:dw|

OpenStudy (anonymous):

y7es

OpenStudy (calculator):

so how do you shade?

OpenStudy (calculator):

|dw:1351516117428:dw|

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