Question

derivative of -(pi/3)sin(pi*t/3) ?

Not sure what to do with the pi over 3 before sin. other than that its just chain rule right?

Answer 1

It's the product rule you should use here.

Answer 2

But actually this is just a constant value! Where is the variable?

Answer 3

Oh is the variable t?

Answer 4

Sorry it is the chain rule plus the product rule for the pi/3 out front. I got:

((-pi)^2/9)cos(tpi/3)

Answer 5

when you use the chain rule and differentiate the (pi/3 sin) part. what happens to the pi over 3?

Answer 6

pi/3 stays as a constant. the derivative of the inside is also pi/3, so it comes out front and you multiply it to the original pi/3 to get -pi^2/9

Answer 7

ok thank you