Question

Rationalize the denominator of...

Answer 1

\[\LARGE \sqrt{18}/\sqrt{3}\]

Answer 2

"sqr root of 18 over sqr root of 3"

Answer 3

Multiply by \(\LARGE {\sqrt 3 \over \sqrt 3}\).

Answer 4

\[\large A) 6\]
\[\large B) \frac{ 2\sqrt{3} }{ 3}\]
\[\large C) \frac{ 3\sqrt{3} }{ 2 }\]
\[\large D) \sqrt{6}\]

Answer 5

BTW, if you want some equation writing tips:

\LARGE \frac{ \sqrt{18} }{ \sqrt 3 }

or:

\LARGE { \sqrt{18} \over \sqrt 3 }

Answer 6

Thanks, I got it :) & Idk the answer to the question you asked up there about multiplying those two...

Answer 7

\[\Large {{ \sqrt{18} \over \sqrt 3 }\cdot{\sqrt 3 \over \sqrt 3}}\]

Answer 8

Remember that \(\LARGE {\sqrt 3 \over \sqrt 3}\large =1\).

Answer 9

Oh, I didn't know that,

Answer 10

\[\sqrt{18}=3\sqrt{2}\]

Answer 11

So where do I go from there?

Answer 12

\[\frac{ 3\sqrt{2} }{ \sqrt{3} }\times \frac{ \sqrt{3} }{ \sqrt{3} }\]

Answer 13

I'm so confused...

Answer 14

\[\sqrt{18}/\sqrt{3} = \sqrt{2*9}/\sqrt{3} =3\sqrt{2}/\sqrt{3}\]

Answer 15

so for you can rationalize the denominator you need multiplie this fraction by (sqrt3)/(sqrt3) so than will get \[3\sqrt{2}/\sqrt{3} *\sqrt{3}/\sqrt{3}=3\sqrt{2}*\sqrt{3}/\sqrt{3}*\sqrt{3}=\]

Answer 16

\[=3\sqrt{6}/3 =\sqrt{6}\]

Answer 17

ok ?


do you understand it now ?

Answer 18

@ExtremeAnon are you here ?

Answer 19

sorry, i was doing another problem. yes, i'm here. & yes i get it now, i think :) thank you!

Answer 20

@jhonyy9

Answer 21

so than yw

was my pleasure

good luck

bye