Write an equation of a line in point slope form that has a slope of -3 and passes through the point (3,-4). Help?
I don't want the answer. I would like someone to actually show me how to work through this! I'm not good with this section in Geometry
Here is the point-slope form. \[(y-y_{0})=m(x-x_{0})\] Substitute and simplify!
But they give me only one pair of points so how exactly do I go about doin this?
You have three things 1) A Point 2) A slope 3) The point-slope form That is all you need. Substitute the points coordiantes into y0 and x0 and the slope in m. You'll be done.
So, would it be (0,-4)=-3(3,0) I'm still a little confused.
If you're going to write the point-slope form, at least write it this way: \[y - y_1 = m(x - x_1)\] You are given \(m = -3\) and \((x_1, y_1) = (3,-4)\). Only substitute what you are given into the equation.
(0,-4)=-3 (3,0) right?
Nowhere in the problem are you given (x,y) = (0,0). If you are not given something, don't substitute it. Not every single variable needs to be substituted.
And also, the formula does not tell you to include any commas.
oh! my bad! But I do not understand what I would put for x and y? would it be y-(-4)=-3(x-3)?
You have it
Since in the left side it is two negatives, would I turn it into a positive? or leave it?
y-(-4) = -3(x-3) is correct, however it should be simplified to y + 4 = -3(x-3)
Good job
Thank you!! Now I understand how to do the rest!(:
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