Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (anonymous):

Evaluate the integral

OpenStudy (anonymous):

\[\int\limits_{0}^{\pi/4} \sec \Theta \tan \Theta d \Theta \]

OpenStudy (anonymous):

i think i've used the wrong theta sign.. but yea..those are just theta

zepdrix (zepdrix):

Hmm this is an identity that you will become fairly familiar with. But if you're just learning it now, let's do it the proper way. :) Change everything to sines and cosines, and we'll then look to see if we can apply a nice u-substitution. Do you remember secant and tangent in sine cosine form? :D

OpenStudy (anonymous):

I just know the antiderivative is sec theta

OpenStudy (anonymous):

so i'm thinking is sec (pi/4) - sec (0)

OpenStudy (anonymous):

oh, and this section is particularly for calculus fundamental theorem

zepdrix (zepdrix):

Oh you do know that integral :) ok cool. So from here, it's probably easier to switch the secants to 1/cos's, then we can try to remember our special angles.

OpenStudy (anonymous):

yep, i got sec pi/4 as sqrt (2), but im not sure about sec 0

zepdrix (zepdrix):

\[\cos(\pi/4)=\frac{ \sqrt2 }{ 2 }\]\[\sec(\pi/4)=\frac{ 1 }{ \cos(\pi/4) }=\frac{ 2 }{ \sqrt2 }=\sqrt2\]So you were able to find this point ok? c: good good. Just gotta remember the cosine of 0 for the next one. \[\cos(0)=1\]\[\sec(0)=\frac { 1 }{ \cos(0) }=\frac{ 1 }{ 1 }=1\] Sorry for slow response :( Open study crashed and made me type this all out again >:c

OpenStudy (anonymous):

oh.. i thought sec 0 will be -1.. cuz i'm thinking u need to flip signs.. umm, i get it now, thanks!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!