Evaluate the integral
\[\int\limits_{0}^{\pi/4} \sec \Theta \tan \Theta d \Theta \]
i think i've used the wrong theta sign.. but yea..those are just theta
Hmm this is an identity that you will become fairly familiar with. But if you're just learning it now, let's do it the proper way. :) Change everything to sines and cosines, and we'll then look to see if we can apply a nice u-substitution. Do you remember secant and tangent in sine cosine form? :D
I just know the antiderivative is sec theta
so i'm thinking is sec (pi/4) - sec (0)
oh, and this section is particularly for calculus fundamental theorem
Oh you do know that integral :) ok cool. So from here, it's probably easier to switch the secants to 1/cos's, then we can try to remember our special angles.
yep, i got sec pi/4 as sqrt (2), but im not sure about sec 0
\[\cos(\pi/4)=\frac{ \sqrt2 }{ 2 }\]\[\sec(\pi/4)=\frac{ 1 }{ \cos(\pi/4) }=\frac{ 2 }{ \sqrt2 }=\sqrt2\]So you were able to find this point ok? c: good good. Just gotta remember the cosine of 0 for the next one. \[\cos(0)=1\]\[\sec(0)=\frac { 1 }{ \cos(0) }=\frac{ 1 }{ 1 }=1\] Sorry for slow response :( Open study crashed and made me type this all out again >:c
oh.. i thought sec 0 will be -1.. cuz i'm thinking u need to flip signs.. umm, i get it now, thanks!
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