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Algebra 14 Online
OpenStudy (anonymous):

Find the center and radius of a circle that has a diameter with endpoints (-9, -6) and (-1,0). Show work. a) center (4,3); radius 5 b) center (8,6); radius 10 c) center (-5,-3); radius 5 d) center (-10,-6); radius 10

OpenStudy (anonymous):

Center would be the midpoint between those two points, and the radius would be the distance between them divided by 2

OpenStudy (anonymous):

So I do the midpoint formula using the two points to find the center?

hero (hero):

Graph paper would work great for this problem

OpenStudy (anonymous):

Yep, use the midpoint formula

OpenStudy (anonymous):

What do you get?

OpenStudy (anonymous):

(-5,-3)

OpenStudy (anonymous):

Yep, what about for the radius?

OpenStudy (anonymous):

I know its suppose to be 5, but I didn't get it.

OpenStudy (anonymous):

Do you know the distance formula?

OpenStudy (anonymous):

Wait, I think I know why..

OpenStudy (anonymous):

I still didn't get it. Isn't it d=\[\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}\]

OpenStudy (anonymous):

Yeah thats it. Plug in your coordinates \[D=\sqrt{(-1+9)^2+(0+6)^2}\]

OpenStudy (anonymous):

youll get d=sqrt{100} d=10 but remember thats the diameter, radius is diameter divided by 2. 10/2=5

OpenStudy (anonymous):

Oh, I got it now. I just added wrong. Thanks!

OpenStudy (anonymous):

You're welcome

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