Question

2nd derivative i have the first!

Answer 1

find the derivative of the first derivative

Answer 2

original is \[x \sqrt{9-x}\]first is \[\frac{ -3x+18 }{ 2\sqrt{9-x} }\]

Answer 3

then you use the quotient rule

Answer 4

i just need help simplifying

Answer 5

where i'm at

Answer 6

any idea?

Answer 7

yea, just try to find out the easiest way to type = ="

Answer 8

?

Answer 9

3(x-12)/(4(9-x)^(3/2))

Answer 10

how did you get that

Answer 11

first, factor out constants: 1/2(d/dx(18-3x)/sqrt(9-x))
use the product rule: and you will get \[\frac{ 1 }{ 2 }\left[(18-3x)( d/dx\frac{ 1 }{\sqrt{9-x} }) \right]+(d/dx\frac{ 1 }{ \sqrt{9-x} })\]
Differentiate the sum term by term and factor out constant:

(first attach file)

Using the chain rule, and you will get (2nd attach pic)

derivative of 18 is zero, and so you will get (3rd)

differentiate the sum term by term and factor out constant (4th)

the derivative of x is 1 (5th)


the derivative of 9 = 0 (6th)

finally the derivative of x =1 (7th)

Answer 12

actually, never mind what attachment, each shows you complete solution