Question

Find the magnitude & direction of the vector JK given points J(-6,-4) & K(-10,-4).

a. 4 units; 180 degrees
b. 16 units; 180 degrees
c. 4 units; 0 degrees
d. 16 units; 0 degrees

Answer 1

magnitude is just the length of the vector given by \[\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\]
Direction is testing whether you know which way a vector goes from definitions. usually JK means from J to K.

Answer 2

ok so it's four units? @freewilly922

Answer 3

yes:)

Answer 4

how to find the degrees becuase there are two answers with four in them

Answer 5

If they give you JL are you moving from
\[j\to k\] or \[k\to j\]

Answer 6

c?

Answer 7

If you think vector jk goes from j to k then it should be 180. If you think it goes from k to j then it is zero.

Answer 8

ok, i think it's a now

Answer 9

becuase i thought it would be like in the alphabet

Answer 10

am i correct?

Answer 11

@freewilly922

Answer 12

I would put (a) because j to k goes into the negative direction which is 180 degrees. generally into the positive x direction (only) is 0 degrees.