Question

Please help me with radicals, it makes NO sense.

Picture below

Answer 1

Where is the picture?

Answer 2

5 ^3 √162

Answer 3

you take 5 and multiply it by the cube root of 162

Answer 4

I was wondering about that '3'. Can you find a perfect cube in 162?

162 = 2*81 = 2*3*27 = 2*3*(3^3)!!!

\[\sqrt[3]{162} = \sqrt[3]{2*3*3^{3}} = \sqrt[3]{2*3}\cdot\sqrt[3]{3^{3}} = \sqrt[3]{6}\cdot 3\] How are we doing? ANY sense at all?

Answer 5

Things are good

Answer 6

How did you get 2 * 81?

Answer 7

I am searching for a "Prime Factorization". I was just thinking about ANYTHING that would divide 162. The first thing I thought of was '2'. After that, it was obvious that there were a bunch of 3's.