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OpenStudy (anonymous):
0.350 L of 0.490 M H2SO4 is mixed with 0.300 L of 0.260 M KOH. What concentration of sulfuric acid remains after neutralization? HELP!
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OpenStudy (anonymous):
I'll write you the equations you do the math. .350l*.49M=moles of sulphuric acid .300*.26M=moles of KOH moles of H2SO4-2*moles of KOH=moles of H2SO4 in neutral moles of H2SO4 neutral/(300+350)
OpenStudy (anonymous):
the 2 is the normality of the acid, you need 2KOH to get 1H2SO4, the acid has 2 acid hidrogens
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