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OpenStudy (anonymous):
do you know how to get rid of natural log?
OpenStudy (anonymous):
start by using both sides as exponents with base e. then subtract 5 from both sides. the answer is (e^3)-5
OpenStudy (anonymous):
no i dont know how to get rid of a natural log
OpenStudy (anonymous):
to solve ln(x) = y, the form of the solution is e^y=x
OpenStudy (anonymous):
ok
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OpenStudy (anonymous):
so if you substitute in (p+5) for x and 3 for y (these are from the original equation) what do you get?
OpenStudy (anonymous):
*substitute them into e^y=x
OpenStudy (anonymous):
e^3=p+5?
OpenStudy (anonymous):
now solve for p
OpenStudy (anonymous):
would i subtract 5?
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OpenStudy (anonymous):
yup. and you can leave e as e or use decimal equivalent
the main point of this is that in an equation of form ln(x)=y, to get rid of ln, you take each side of the equation as an exponent with e as the base. this will get rid of the ln
OpenStudy (anonymous):
oh ok
OpenStudy (anonymous):
once i have subtracted the 5 how should it then look like?
OpenStudy (anonymous):
(e^3)-5
OpenStudy (anonymous):
decimal approximation = 15.086
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OpenStudy (anonymous):
either way works (left as e or decimal approximation)