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Mathematics 18 Online
OpenStudy (anonymous):

ln(p+5)=3

OpenStudy (anonymous):

do you know how to get rid of natural log?

OpenStudy (anonymous):

start by using both sides as exponents with base e. then subtract 5 from both sides. the answer is (e^3)-5

OpenStudy (anonymous):

no i dont know how to get rid of a natural log

OpenStudy (anonymous):

to solve ln(x) = y, the form of the solution is e^y=x

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

so if you substitute in (p+5) for x and 3 for y (these are from the original equation) what do you get?

OpenStudy (anonymous):

*substitute them into e^y=x

OpenStudy (anonymous):

e^3=p+5?

OpenStudy (anonymous):

now solve for p

OpenStudy (anonymous):

would i subtract 5?

OpenStudy (anonymous):

yup. and you can leave e as e or use decimal equivalent the main point of this is that in an equation of form ln(x)=y, to get rid of ln, you take each side of the equation as an exponent with e as the base. this will get rid of the ln

OpenStudy (anonymous):

oh ok

OpenStudy (anonymous):

once i have subtracted the 5 how should it then look like?

OpenStudy (anonymous):

(e^3)-5

OpenStudy (anonymous):

decimal approximation = 15.086

OpenStudy (anonymous):

either way works (left as e or decimal approximation)

OpenStudy (anonymous):

ok

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