Question

by what number must both sides be multiplied in order to solve 5/7y =8

Answer 1

solve for y?

Answer 2

its says what both sides be multiplied in order to solve the equation 5/7y = 8

Answer 3

can you clarify if it is "five sevenths times y equals 8" ?

Or is it 5/(7y) = 8 ?

In other words, is the y in the denominator?

Answer 4

no its 5/7 y is for both = 8\[\frac{ 5 }{ 8 }y=8\]

Answer 5

its seven not 8

Answer 6

so you need to multiply both sides by a number that will cause y to be all by itself on the left after...

they are wanting you to think about inverses of fractions...

if you have (5/7) y on the left, you can multiply by the inverse of (5/7) which is (7/5)

So (5/7) y = 8
Multiply both sides by the inverse of the fraction in front of the "y"...
(5/7)(7/5) y = (8)(7/5)
then the fractions on the left cancel out, leaving just y
y = 8(7/5) = 56/5

Answer 7

ok that makes sense this is a linear equation so it makes sense

Answer 8

ok, glad to help :)

Even if the y-term didn't look like it had a fraction, like 8y, you could still treat that like a fraction like (8/1)y... then you would multiply both sides by the inverse, which would be (1/8) to cancel the stuff in front of the "y".

That's obviously the same thing, in different words, to saying you divide both sides of the equation by 8 to solve for y if you started with 8y.

Answer 9

you rock