Question

how do i find the horizontal asymtotes of f(x)=(1/(x-2))-3?

Answer 1

do you know what the horizontal asymptotes of the graph 1/x are?

Answer 2

0.

Answer 3

y=0
yes
do you understand shifts/transformations in graphs?

Answer 4

yup. this would be 2 to thr right and 3 down

Answer 5

i get where this is going. thank u!

Answer 6

how would i do it for a function like 3x/(x^2-1)

Answer 7

hmmm...idk just by looking at it..i can figure it out in 5 mins, ok?

Answer 8

it's cuz we r trying to figure out how to draw a graph by using symm, concavity, critical no's, and intercepts. no calc alowd :(

Answer 9

ok think of it this way
an asymptote is a number that a graph approaches
a horizontal asymptote is what the graph's y values approach as x goes to -infinity or +infinity
if you plug in really big numbers, you can recognize that the denominator is growing faster than the numerator (its a polynomial of higher degree)
if you have a fraction, and the denominator is getting bigger than the numerator, the fraction goes to zero
therefore, as x goes to infinity (to either + or -, it works for both), the function goes to zero, but will never touch it (except at x=0, but thats not what we r looking at)

Answer 10

ohhh! I remember noww x) haha thank you!

Answer 11

http://answers.yahoo.com/question/index?qid=20071124212550AAMpbIb
heres a link if you need more help