Question

find the velocity of an object dropped from a height of 300 m at the moment it hits the ground?

Answer 1

v = SQRT(2gx) or v = √(2gx)

G (gravity) = 9.81 M/s/s
x = 300m

So, putting the numbers in the formula we get.

v = Square root of (2 x 9.81 x 300)

V = sq rt of 5886

V = 76.72 m/s

Answer 2

i dont have to use this equation when solving? \[s(t)= s _{0}+ v _{0}t - .5 g t ^{2}\]

Answer 3

no. becuase there is no time in your equation. that equation would be needed if you had a time.