what is the perimeter of the triangle with vertices L=(1,5) , M=(-3,-3) ,and N=(3,1) ?
Do you know the point distance formula?
yup
So, calculate the distance from L to M.
16sqrt 5
Not exactly, you are a little off
its 4sqrt5
yes opps
M to N it's sqrt 97
Okay, So I did the calculations and I got 4sqrt5, 2sqrt13, 2sqrt5. Now add all of these together.
Can you add those values together?
BTW are you looking for an exact value or approx?
2sqrt 13 +6 sqrt5
Root 80 + Root 52 + Root 20. Another way of completing this question is to use Pythagoras theorem, and its arguably quicker. Just take the difference in x values between two points, and the difference in y values then apply: Length^2=x-change^2+y-change^2 For each of the length's then add together. I agree entirely with @Zordoloom method, but i am providing an alternate.
its 2sqrt3, +6sqrt5
Does that answer your question?
no it's the answer
i didnt understand the alternate method @Henry.Lister
So do I get a medal?
|dw:1351590008433:dw| I know its not precise, but this is our triangle right?
We can split it up into 3 seperate triangles.
how?
|dw:1351590103132:dw|
|dw:1351590177723:dw|
|dw:1351590225180:dw|
i got it
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