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Mathematics 20 Online
OpenStudy (anonymous):

what is the perimeter of the triangle with vertices L=(1,5) , M=(-3,-3) ,and N=(3,1) ?

OpenStudy (anonymous):

Do you know the point distance formula?

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

So, calculate the distance from L to M.

OpenStudy (anonymous):

16sqrt 5

OpenStudy (anonymous):

Not exactly, you are a little off

OpenStudy (anonymous):

its 4sqrt5

OpenStudy (anonymous):

yes opps

OpenStudy (anonymous):

M to N it's sqrt 97

OpenStudy (anonymous):

Okay, So I did the calculations and I got 4sqrt5, 2sqrt13, 2sqrt5. Now add all of these together.

OpenStudy (anonymous):

Can you add those values together?

OpenStudy (anonymous):

BTW are you looking for an exact value or approx?

OpenStudy (anonymous):

2sqrt 13 +6 sqrt5

OpenStudy (anonymous):

Root 80 + Root 52 + Root 20. Another way of completing this question is to use Pythagoras theorem, and its arguably quicker. Just take the difference in x values between two points, and the difference in y values then apply: Length^2=x-change^2+y-change^2 For each of the length's then add together. I agree entirely with @Zordoloom method, but i am providing an alternate.

OpenStudy (anonymous):

its 2sqrt3, +6sqrt5

OpenStudy (anonymous):

Does that answer your question?

OpenStudy (anonymous):

no it's the answer

OpenStudy (anonymous):

i didnt understand the alternate method @Henry.Lister

OpenStudy (anonymous):

So do I get a medal?

OpenStudy (anonymous):

|dw:1351590008433:dw| I know its not precise, but this is our triangle right?

OpenStudy (anonymous):

We can split it up into 3 seperate triangles.

OpenStudy (anonymous):

how?

OpenStudy (anonymous):

|dw:1351590103132:dw|

OpenStudy (anonymous):

|dw:1351590177723:dw|

OpenStudy (anonymous):

|dw:1351590225180:dw|

OpenStudy (anonymous):

i got it

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