Question

hey i need help
The sum of the squares of 2 consecutive negative integers is 41. What are the numbers?

Which of the following equations is the result of using the factoring method to solve the problem?
(n - 5)(n - 4) = 0

(n - 5)(n + 4) = 0

(n + 5)(n - 4) = 0

(n + 5)(n + 4) = 0

Answer 1

let the both numbers are -n and -(n+1)

Answer 2

so, (-n)^2 + (-(n+1))^2 = 41
n^2 + (n+1)^2 = 41
n^2 + n^2 + 2n + 1 - 41 = 0
2n^2 + 2n - 40 = 0
both sides just divide by 2,
n^2 + n - 20 = 0
(n + 5)(n - 4) = 0

Answer 3

now can you help me with this one
The sum of the squares of 3 consecutive positive integers is 116. What are the numbers?



Which of the following equations is used in the process of solving this problem?

3n2+ 5 = 116

3n2+ 3n + 3 = 116

3n2+ 6n + 5 = 116

Answer 4

let that numbers are : n, n+1 and n+2. so,
n^2 + (n+1)^2 + (n+2)^2 = 116
n^2 + n^2 + 2n + 1 + n^2 + 4n + 4 = 116
3n^2 + 6n + 5 = 116

Answer 5

i dont have an answer like that

Answer 6

the last option, right ?

Answer 7

never mind its right

Answer 8

ok can you help me with some more

Answer 9

but, i think there is a problem with that question...

Answer 10

no it says its right

Answer 11

The square of a number is equal to 10 less than 7 times that number. What are the two possible solutions?
Which of the following equations is used in the process of solving this problem?

x2- 7x + 70 = 0

x2- 7x + 10 = 0

x2+ 7x - 10 = 0

i need help with this one

Answer 12

if i want to solve for n,
3n^2 + 6n + 5 = 116
3n^2 + 6n + 5 - 116 = 0
3n^2 + 6n - 111 = 0
both sides divide by 3,
n^2 + 2n - 37 = 0
it can not be factorizing, it means that the numbers are not integer number!!

Answer 13

so, the 2nd is a wrong question (statemen)

Answer 14

*statement

Answer 15

ok iam lost now

Answer 16

n^2 + 2n - 37 = 0
to find the its solution, we use quadratic formula :