Question

kkkkk

Answer 1

can you give me the derivative of f ??

Answer 2

that's all it says :// :(

Answer 3

yes... but you need to calculate the derivative of f to find the relative max/min of the function.

Answer 4

isn't this for a calculus class?

Answer 5

algebra 2

Answer 6

oh... sorry....

Answer 7

its okay :) so you don't know how to do it? :(

Answer 8

i know how to do it on a calculater ..but i left it at a friends house ://

Answer 9

oh... so you're allowed to use the max/min functions of a graphing calculator?

Answer 10

yes

Answer 11

ok... hang on...

Answer 12

okaay :)

Answer 13

since you don't have your graphing calculator with you, use this online one....
https://www.desmos.com/calculator

i've also included the graph of your function here:

Answer 14

it looks like you have a relative max at x=-4 and a relative min at x=0

Answer 15

yeah, but that's not one of my options :(

Answer 16

the function you gave at the start does not coincide with those choices...

Answer 17

thats what it says in my homework

Answer 18

i double checked with this function you gave at the start: \(\large f(x)=x^3+6x^2-36 \)
f has a relative max at x=-4 and a relative min at x=0.

Answer 19

f(-4) = -4 so (-4, -4) is a relmax
f(0) = -36 so (0, -36) is a relmin

Answer 20

but that's none of the options ://

Answer 21

i'm sorry.... i'm absolutely sure of my answer here..
even the calculator verifies my answer....

is this the function we started with correct?

Answer 22

yes it is ..hmm :// :(

Answer 23

im just going to pick a or b:///.. lol ..thank you for the help though :)

Answer 24

idk what to say... :(

Answer 25

do you think you could help me with another one?

Answer 26

there has to be an error in those choices...
yw... :)

Answer 27

yes...

Answer 28

What is a cubic polynomial function in standard form with zeros 1, –2, and 2?

Answer 29

do you know how to multiply out binomials?

Answer 30

i know i have to write like (x+1)(x-2)(x+2)

Answer 31

standard form for a cubic polynomial is: \(\large y=ax^3+bx^2+cx+d \)
where a, b, c, d are real numbers.

Answer 32

not quite... since the zeros are 1, -2, and 2,
then the factors are (x-1)(x+2)(x-2)

Answer 33

so all you do is multiply out the 3 binomials....

Answer 34

how is it -1 when it says 1 ?

Answer 35

a zero refers to where the graph crosses the x-axis (when y=0)
so the equation is 0 = (x-1)(x+2)(x-2)
if x=1, you'll have 0 = (1-1)(1+2)(1-2) which is a true statement
but if you have what you wrote down, 0 = (1+1)(1+2)(1-2) is not a true statement

Answer 36

multiply out the binomials: (x-1)(x+2)(x-2) = \(\large x^3-x^2-4x+4 \)

Answer 37

thanks :)