Mathematics
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OpenStudy (amtran_bus):
Prove .99999999999999999999999999999999999999999999999999999 equals 1.
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OpenStudy (anonymous):
that is false.....the number mentioned above ROUNDS UP to 1....meaning it is closer to one than it is to 0 :)
OpenStudy (amtran_bus):
Good job! Now try .9 repeating!
OpenStudy (anonymous):
its the exact same explanation thou stubborn being
OpenStudy (asnaseer):
If you mean 0.999... (i.e. 9's repeating for ever) then this can be proved
OpenStudy (amtran_bus):
Go fir it!
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OpenStudy (asnaseer):
is this a challenge or are you looking for help in trying to prove it?
OpenStudy (amtran_bus):
I want to prove it.
OpenStudy (asnaseer):
ok, start by setting:\[x=0.999..\]Then see what happens if you multiply both sides by 10
OpenStudy (amtran_bus):
10x=0.999(10)
OpenStudy (amtran_bus):
or 9.999999999---
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OpenStudy (amtran_bus):
10=9.99999999 on and on
OpenStudy (asnaseer):
correct - and now notice that 9.99... can be written as 9 + 0.999...
OpenStudy (amtran_bus):
right
OpenStudy (asnaseer):
and what is 0.999.... (look at how we started the proof)
OpenStudy (amtran_bus):
you mean =x?
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OpenStudy (asnaseer):
perfect!
OpenStudy (asnaseer):
so you end up with:
x = 0.999...
10x = 9.999... = 9 + 0.999... = 9 + x
OpenStudy (amtran_bus):
ohhhhh. Thanks!!!
OpenStudy (asnaseer):
yw :)
OpenStudy (phi):
how about x=0.9999...
10x= 9.9999...
10x-x = 9
9x=9
x=1
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OpenStudy (asnaseer):
thats basically exactly what we have done :)
OpenStudy (phi):
yes, just wanted it all in one post for other readers