How do I find dy/dx(8√8x^7-10)??

Question

zepdrix · Answer

Step 1, leave the badgers alone! >:O

Lemme make sure I'm reading the problem right,
$$\large \frac{ d }{ dx }(8\sqrt{8x^7}-10)$$
Does that look right? :O

anonymous · Answer

$$\left(\begin{matrix}dy \ dx\end{matrix}\right) \times (\sqrt[8]{8^{7}-10})$$

zepdrix · Answer

? :O

anonymous · Answer

sorry thats dy/dx

zepdrix · Answer

$$y=(8\sqrt{8x^7-10})$$
Find dy/dx.

So this is what the problem is asking I guess :) It was just worded a little poorly, so I wanted to clarify :3

zepdrix · Answer

So you need to find a derivative yes? :D

anonymous · Answer

okay I think

anonymous · Answer

yes

zepdrix · Answer

If we rewrite the squareroot as a fractional exponent, it will allow us to easier recognize what to do next.$$\large y=8(8x^7-10)^{\frac{ 1 }{ 2 }}$$

anonymous · Answer

I thought it would be y=(8x^7-10)^(1/8)?

zepdrix · Answer

Oh that's an 8th root? ah my bad. I thought it was a coefficient, ok 1/8 then :)

anonymous · Answer

okay :)

zepdrix · Answer

From here we can apply the power rule yes? :D we'll have to apply the chain rule after that though :O

anonymous · Answer

okay I understand now. Thank you!!