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loga16=4
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Log_a(16)=4 is saying that A raised to the 4th power is 16. So, A^4=16, or a=2
and how is it two
any logarithmic equation can be written in exponential form: \(\large log_aM=n \) means \(\large a^n=M \)
okay i get that but so this is the answer a^4=16 ?
@dpaInc
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no... the question is to find "a" so... \(\large a^4=16 \) \(\large [a^4]^{\frac{1}{4}}=[16]^{\frac{1}{4}} \) \(\large a^{\frac{4}{4}}=16^{\frac{1}{4}} \) \(\large a=\sqrt[4]{2\cdot 2\cdot 2\cdot 2}=2 \)
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