Question

The price (in dollars) p and the quantity demanded q are related by the equation: p^2+2q^2=1100.If R is revenue, dR/dt can be expressed by the following equation: dR/dt=A*dp/dt,
where A is a function of just q.

A = ?

Find dR/dt when q=15 and dp/dt=5.
dR/dt = The price (in dollars) p and the quantity demanded q are related by the equation: p^2+2q^2=1100.If R is revenue, dR/dt can be expressed by the following equation: dR/dt=A*dp/dt,
where A is a function of just q.

A = ?

Find dR/dt when q=15 and dp/dt=5.
dR/dt = @Mathematics

Answer 1

i got the first part. dont know the second. did you complete all the other webwork questions?

Answer 2

did you get #13 second part or 14?

Answer 3

i got the second part, i don't get the first part?

Answer 4

#14 0.026 ft/min

Answer 5

i got 14. only 13 2nd part left. do you know?
i have all the others if you need help

Answer 6

13 first part please, second part answer is -26.67

Answer 7

thats wrong for me. first part is (2q-550/q)

Answer 8

how did you get your 13 b?

Answer 9

my q = 20 and dp/dt= 3

Answer 10

R = pq
R' = pq' + p'q

q=15 p'=4

you can calculate for p using the first equation that is given p^2+2q^2=1100
you'll get p= sqrt(650)

then you find q' by differentiating p^2+2q^2=1100 and sub the numbers in
you'll get q'=-3.3 something

then plug them all into R' = pq' + p'q and you'll get the answer

Answer 11

ohhh, that's why

Answer 12

ok let me try. good explanation

Answer 13

ok so i got -6 instead of -3.3

Answer 14

i am lost after that. can you help

Answer 15

you there?

Answer 16

your number is different, so your answers wont match mine

Answer 17

after that just plug everything in R' = pq' + p'q and you'll get R'