Question

solve for yfor both equations x-3y=3 & x+3y=9

just need to know if im right, compare answers?

Answer 1

so for both of the equations get y by itself

Answer 2

x-3y=3
-x -x
3y= -x +3
divide by -3
y= 1/3x ? thats my answer for the first equation


x+3y=9
-x -x
3y= -x +9
divide by 3
y= -1/3+3 ? thats my answer for the second

am i right? & how would i graph i this?

Answer 3

got this for the first one y = (x-3)/3
and how did you get rid of the x on the second equation

Answer 4

the graph is for this equation :y= -1/3+3

Answer 5

y = (9-x)/3 for second

Answer 6

on the first equation you dropped the negative

Answer 7

nvm you didnt my bad

Answer 8

how do i graph the second equation?

Answer 9

i did that :D

Answer 10

i mean how do i graph both equations,?

Answer 11

In the first equation:
x - 3y = 3
Subtract x.
-3y = -x + 3
Divide by -3.
y = 1/3 - 1

To graph, remember that this is Slope-Intercept form. y = mx + b, where m is slope, and b is the y-intercept.

First plot the y-intercept on the graph. y-intercept is where the line crosses the y-axis, so you would plot the point on (0, -1).

Now is when the slope comes in. Remember slope is rise/run. rise = 1, run = 3.
From (0, -1) RISE up 1 space, then RUN to the right 3 spaces. You'll end up on point (3, 0).

Draw a line through points (0, -1) and (3, 0)

Answer 12

one equation is y = 1/3x - 1

Answer 13

To graph #2, do the same. Plot the y-intercept and use slope(rise/run) to find another point. Then draw a line in between.
y = -1/3 + 3

Answer 14

For #2... The RISe will actually go down 1 space, since it is a -1.

Answer 15

Here try this Web site!
www.mathway.com
Let me know if this helps!