Solve 3x^{2}+4x-4=0 by completing the square. Please explain the steps please. I got lost in the part where you're supposed to divide by 2 and square b?
can someone help @amistre64 @Hero @ash2326 @experimentX
first make the co-efficient of x^2 as 1 by dividing both sides by 3, what u get ?
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correct, so now your co-efficient of x = b = 4/3, divide it by 2, what u get ?
2/3
I don't understand what I have to do for the rest of the problem @hartnn
now square that, what u get ?
you're not supposed to square root? uh, 4/9
no, not square root, u need to square it, and 4/9 is correct! so , now add 4/9 on both sides, what u get ?
x^2 + 4/3x+4/9 = -8/9
correct . now u notice that left side is a perfect square and can be written in the form (x+a)^2 can u write it in that form ?
I need to go, I'll check back later :(
no problem.
is this problem an unfinished business?
I don't understand, so (x+x^2)? @sirm3d yeah, I'm still confused on how to solve the rest of the problem :(
the left side of the equation should now be \[\left( x+\frac{ 2 }{ 3 } \right)^{2}\]
the trick is to get the square root of the first and last terms of the left side of the equation enclose by a paor of parenthesis, and square it
so I set that left side you gave me and the right to = -8/9
It's confusing because I had to turn the 2/3^2 to a 4/9 before and now I'm changing it back? @sirm3d
it is necessary in completing squares
you have to square (2/3) to get a perfect square trinomial expression on the left side of your equation
\[(x+2/3)^2=-8/9\]
it would be an i number for the square root of -8/9?
yes
\[x+2/3=i 0.942809042
\[x+2/3=i0.942809042\]
that doesn't look right..
\[x+\frac{ 2 }{ 3 }=\pm \frac{ 2i \sqrt{2} }{ 3 }\]
x_x any little short explanation on how you got the right side?
you're literally saving my life right now lol (I have a quiz tomorrow morning, well today actually cause it's 4am and I'm still awake from a trippy halloween)
the square root of a fraction is a fraction of square roots \[\sqrt{\frac{ 8 }{ 9 }}=\frac{ \sqrt{8} }{ \sqrt{9} }\]
the i number is necessary because the right side is negative, -8/9
Oh! so you do each separate not as a whole.
I could just leave that as my final answer since both are gonna be imaginary right?
yes
Thank you so much!
it would be best to direct that question to your teacher, since he/she will be the one to check answers
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