Question

Solving Equations Quadratic in Form:

x^4-13x^2+36=0

Answer 1

\[x^{4}-13^{2}+36=0\]

Answer 2

@jim_thompson5910 can you help me I am stuck on this problem

Answer 3

Have you tried letting z = x^2

So z^2 = (x^2)^2 = x^4

So z = x^2 and z^2 = x^4

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This means that

x^4-13x^2+36=0

becomes

z^2-13z+36=0

Answer 4

Now ignore everything else for now

Answer 5

and solve z^2-13z+36=0

Answer 6

that is where I am at but I can't seem to find anything that adds up to 13 and and 36 (x+)(x-)

Answer 7

@jim_thompson5910

Answer 8

how about -9 and -4

Answer 9

OMG I should take a break cause that was so simple. Maybe not feeling well and math are not good together

Answer 10

true, but you'll get better at both

Answer 11

thank u @jim_thompson5910 I can always rely on you

Answer 12

you're welcome

Answer 13

keep in mind once you have 2 solutions for z, you use them to find the solutions for x (you'll get 4 solutions total for x)