Question

A force of 9.0 x 10^-5 N is the force of attraction between Mass A and Mass B at a certain distance apart. If the mass of Mass B is doubled (but Mass A stays the same), what is the value of the force between the two masses at the same distance?

Answer 1

so it be 2?

Answer 2

@chme

Answer 3

The answer would be 9.0 x 10^-5 times 2. whatever that is.

Answer 4

ok

Answer 5

\[F=G \frac{ m_{1}m_{2} }{ r^2 }=9.0\times10^-5\]\[F=G \frac{ 2m_{1}m_{2} }{ r^2 }\]\[F=2(G \frac{ m_{1}m_{2} }{ r^2 })=2\times(9\times10^-5)\]

Answer 6

There is a better show of the owrk, sry if you were confused at first

Answer 7

thx